Could Someone Explain These Situations?
Posted: Tue Jul 03, 2007 10:43 pm
I saw these plays in my boxscore last night, but I did not understand how they happened. If someone could explain them, especially in a way that could be recreated on the board game version, I'd greatly appreciate it.
Here's the first play:
*** TOP OF INNING 3 ***
0 J.Robinson 4 Walk b-1
0 1 F.Robinson 3 Single (CF) 1-2 b-1
0 12 E.Banks 4 Fly Out (LF) b-0
1 12 E.Murray 5 Single & Error - RF 2-H 1-H b-3 bpSI 1-12
1 3 J.Rice 4 Line Out (SS) b-0
2 3 D.Baylor 5 Fly Out (CF) b-0
I thought a Ballpark single was only good for one base (SI*), so what happened on this play? How did runners on first and second both score with the batter going to third? I assume it was treated as a straight single to RF, and that a throwing error (to third base?) resulted in a 2-base error, but I couldn't simulate it on the board.
Second play:
*** TOP OF INNING 9 ***
0 J.Rice 1 1 Base Error - P b-1 gb(P)x
0 1 D.Baylor 5 Single (2B) 1-3 b-1 gb(2B)x
SUBSTITUTE P - Daryl Patterson
0 1 3 L.Parrish 4 Sac Fly (CF) 3-H b-0
1 1 S.Garvey 3 Strike Out b-0
2 1 G.Bell 5 Ground Out (2B) b-0 gb(2B)x
This was in the same game as the first example. With a runner on 1st, the batter rolls a gb(2B)x. Second baseman is a 2, so the single I would expect would be only a one-base hit (SI*). So how does Rice make it over to 3rd base on the play?
As I said, if someone can take the time to explain these situations, it would help me better understand this simulation.
Thanks,
Tom
Here's the first play:
*** TOP OF INNING 3 ***
0 J.Robinson 4 Walk b-1
0 1 F.Robinson 3 Single (CF) 1-2 b-1
0 12 E.Banks 4 Fly Out (LF) b-0
1 12 E.Murray 5 Single & Error - RF 2-H 1-H b-3 bpSI 1-12
1 3 J.Rice 4 Line Out (SS) b-0
2 3 D.Baylor 5 Fly Out (CF) b-0
I thought a Ballpark single was only good for one base (SI*), so what happened on this play? How did runners on first and second both score with the batter going to third? I assume it was treated as a straight single to RF, and that a throwing error (to third base?) resulted in a 2-base error, but I couldn't simulate it on the board.
Second play:
*** TOP OF INNING 9 ***
0 J.Rice 1 1 Base Error - P b-1 gb(P)x
0 1 D.Baylor 5 Single (2B) 1-3 b-1 gb(2B)x
SUBSTITUTE P - Daryl Patterson
0 1 3 L.Parrish 4 Sac Fly (CF) 3-H b-0
1 1 S.Garvey 3 Strike Out b-0
2 1 G.Bell 5 Ground Out (2B) b-0 gb(2B)x
This was in the same game as the first example. With a runner on 1st, the batter rolls a gb(2B)x. Second baseman is a 2, so the single I would expect would be only a one-base hit (SI*). So how does Rice make it over to 3rd base on the play?
As I said, if someone can take the time to explain these situations, it would help me better understand this simulation.
Thanks,
Tom