by FAaron » Thu Jan 05, 2006 9:53 pm
I think the general view is that 3s or 4s at SS/2B/CF is just not workable with the few players eligible who fit that dubious distinction. I think the best solution is for each team to fill the 3 spots with an aggregate 8 at best (ie, a 2 and two 3s, or two 2s and one 4, or a 1, a 3 and a 4).