by ClowntimeIsOver » Mon Jan 07, 2008 10:32 pm
on average, his OPS would be at least 210 points lower than in an average park (when the roll was on his card, which is half the time) in a 1/1 park -- and at least 105 points lower in a 5/5 or 6/6 park
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you can estimate park effect on OBA by looking at the rolls that have a park symbol, which for Dye are:
vs. L: rolls of 3,2,3,7,11 = chances (out of 3X36 dice combinations) of 2+1+2+6+2 = 13 PA (out of 108 PA) = park has an effect on 13/108 PA
vs. R: 3,4,3,6,12 = 2+3+2+5+1 = 13 (out of 108)
it's the same for left and right -- 13/108
13/108 means it would be half that much in an average 10/10 park, or 6.5 times on base per 108 PA (because an average park creates a 50/50 chance)
so in a 1/1 park, it would be 0.1 x 6.5 "park effect" times on base per 108 PA (a tenth of average), and in a 19/19 park it would be 1.9 x 6.5 /108
when the roll is on his card (not the pitcher's): in a "1/1" park, he'd have 5.85 fewer times on base per 108 PA than in an average (10/10) park, and in a 19/19 park he'd have 5.85 times more than average -- so, for starters, his OBA would be .054 lower in the most extreme pitchers' park when the roll is on his card
SLG is too time-consuming to figure so quickly, but HR/PA is an easy substitute:
vs. L: 7,11 = 6+2 = 8 "park effect" HR chances per 108 PA
vs. R: 3,6,12 = 2+5+1 = ditto
in an average 10 park: 4 "park-effect" HR per 108 PA, when on his card
so, when on his card, in a 1 park he'd have 3.6 fewer "park effect" HR per 108 PA than in an average park (and he'd have 3.6 more than average in a 19 park)
that suggests his SLG is reduced by at least 150 points on lost HR's alone in a 1 park, and probably a lot more when you realize the above is PA and not AB
so OPS in a 1/1 park would be at least 210+ points lower when the roll is on his card, and at least 100+ points lower in a 5/5 or 6/6 park
this is easier to figure out than it sounds -- all you have to do is add up a few single-digit numbers in your head -- takes a minute or so adding it up by eye when you learn to do it:
2,3,4,5,6 roll = 1,2,3,4,5 times out of 108
ditto the reverse: 12,11,10,9,8 roll = 1,2,3,4,5 times
7 roll = 6 times
you add it up, use half the total for an average park, and then the maximum park effect is +/- 0.9 times the average park total