Just in case you ever wanted to know...

Our Mystery Card games - The '70s Game, Back to the '80s, Back to the '90s

Just in case you ever wanted to know...

Postby bjs73 » Mon Jan 16, 2006 9:09 pm

I posted this in the main Strat-O board as a response to question about the probability of the dice and how it relates to the cards we play. Sorry about the cross post here but it's been slow here lately and this is my favorite board of them all.

[quote:88d233f59e]I believe that I've got the probabilities correct but please someone else come and correct me if I'm wrong. I will focus on any position player's "1" column and you can roll it out to the "2-6" columns because they are the same.

For the sake of simplicity the first number represents 1d6 followed by a dashed number which represents 2d6.

1-2 = 0.46%
1-3 = 0.93%
1-4 = 1.39%
1-5 = 1.85%
1-6 = 2.31%
1-7 = 2.78%
1-8 = 2.31%
1-9 = 1.85%
1-10 = 1.39%
1-11 = 0.93%
1-12 = 0.46%

Take all of these percentages and multiply by 6 columns and you get:
99.96%

Seriously, the missing .04% is there, I just rounded the above numbers to the nearest hundredth. There are some incredibly long decimals after those figures so if you really want to find that missing .04%, use your own calculator! LOL

How did I arrive at the figure? First die is a 1/6 chance multiplied by the outcome of two dice. There are 36 possibilities on a 2d6 throw. 1/36 to roll a 1 or 12, 2/36 to roll a 3 or 11, 3/36 to roll a 4 or 10, etc., etc.

Hope this helps?[/quote:88d233f59e]
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Postby nycalderon » Mon Jan 16, 2006 11:16 pm

this is correct...

the easier way to arrive at the same numbers is to calculate the number of ways you can arrive at any single outcome... for example how many ways can you get a dice roll of "6" on the batters' "1" column, which is 5. And divide that number by the total number of possible combinations - 216. So for the example I have given 5/216 equals .0231. So you will hit a "6" on the batters 1 column 2.31 times out of 100 chances on average.
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Postby PillPop » Tue Jan 17, 2006 12:50 pm

"The easier way"?
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Chances per Die

Postby YountFan » Tue Jan 17, 2006 1:13 pm

D=# where D is dice and # is number of chances (or # of ways to get it)
2=1
3=2
4=3
5=4
6=5
7=6
8=5
9=4
10=3
11=2
12=1
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SHHHhhhhhhh

Postby Panzer ace » Tue Jan 17, 2006 9:01 pm

Dont tell honestiago about this thread...we dont want to start this up again..... :roll:
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