A question regarding wild pitches

how does the game engine decide when a pitcher with a rating of bk- 6 wp- 0 throws a wild pitch?

SUBSTITUTION at P: Mike Garman (role: RH Specialist)
2 12 W.Mays 5-3 Ground Out (1B) b-0 gb(1B)x F9
BOTTOM OF INNING 9
0 M.Ruel 3-5 Pop Out (3B) b-0 F9
1 R.Thomas 4-9 Ground Out (SS) b-0 gb(SS)x F9
2 O.Charleston 6-10 Fly Out (CF) b-0 fly(CF)x F9
TOP OF INNING 10
0 R.Clemente 1-8 Walk b-1 F9
0 1 L.Smith Wild Pitch 1-2 catch-x F9
0 2 L.Smith 5-9 Ground Out (3B) 2-3 b-0 F9
1 3 R.Smith 3-9 Fielders Choice (SS) 3-H b-1 F9
1 1 F.Duncan 2-4 Single (CF) 1-2 b-1 F9
1 12 H.Wagner 6-7 Force Play (SS) 2-3 1-o b-1 F9
2 1 3 K.Cuyler 6-12 Fly Out (LF) b-0 F9

-steven

This was a catcherX roll and therefore does not refer to the pitcher's WP rating

It looks like Muddy Ruel (1924?) is the catcher. The '24 Ruel is 1e6.

On a CATCH-X roll, there is a 15% (3-in-20) chance of getting W/G and a 5% chance of W/S. For both results, if no error or rare play occurred, then a wild pitch is thrown. For an e6 catcher, there are 21 chances in 108 to get E1, E2, or RP. So, 87 chances for a wild pitch or 81%.
So, overall, that's a 16% chance of a wild pitch on a CATCH-X with an e6 catcher, as long as someone in on base.
Getting a CATCH-X roll is just 3-in-216 to begin with. So, 16% of 1.4%, as long as a runner is on base.

thank you palanion for the input. there was a runner on 1st.

-steven