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He might be reading it right, because that is what it seems to say, but as BBFAN says here, that number seems way too high to be based just on the chances of a particular position having a fielding chance, and then successfully or not dealing with that chance.
Just a flier with the math, but if there are 5 plate appearances per side per inning, that is 45 plate appearances a game for a nine inning game Even using a SS, with their 6/216 chance of an X-chart reading, that would by my math and figures give 1.25 X-chart chances a game. Other positions would have even fewer chances per game. So, if every SS x-chart result gave an inside the park homerun, that still only costs (1.25 x 4) or 6 TB a game. No? Obviously, I am estimating what I think is "worst case" scenarios to err on the side of caution. Am I off somewhere on the logic and/or process?